Derivative Tips 101 (Sunday, November 20, 2016)

1. Need to find the derivative of a function in Calculus? Then this might help youRemove all variables in the function (ex: 5x2 + 3x + 5 = y --> 52 + 3 + 5 = 0)

2. Replace all numbers greater than 5 with a zero (52 + 3 + 5 = 0 --> ex: 02 + 3 + 0 = 0)

3. Add 10 to every number (ex: 02 + 3 + 0 = 0 -->  1012 + 13 + 10 = 10)

4. Divide everything by 4 (ex: 1012 + 13 + 10 = 10 --> 2.53 + 3.25 + 2.5 = 2.5)

5. Change every 2.5 with an x (ex: 2.53 + 3.25 + 2.5 = 2.5 -->  x3 + 3.25 + x = x)

6. Remove every number keeping the variables (ex:  x3 + 3.25 + x = x --> x + x = x)

7. Simplify (ex: x + x = x --> x=0)

8. Change 0 to y, and x to 10x + 3 (ex: x=0 --> 10x + 3 = y)

Fake Tips

    -Tyler Johnson